Rules for **Divisibility** A number is **divisible**: By 2, if it is an even number. By 5, if the number has a 0 or a 5 in the ones' place. By 10, if the number has a 0 in the ones' place. By 3, if the sum of the digits is **divisible** by 3. By 9, if the sum of the digits is **divisible** by 9.

**Divisibility** Rules Chart LOOK AT THE DIGIT IN THE ONES PLACE! 2 Last digit is even 5 Last digit is a 5 or 0 10 Last digit is 0 CHECK THE DIGIT SUM! 3 Sum of digits is **divisible** by 3 6 Number is **divisible** by 3 AND 2 9 Sum of digits is **divisible** by 9 LOOK AT THE LAST DIGITS! 4 Last 2 digits form a ...

EQUATIONSSOLV ABLE BY RADICALS IN A UNIQUELY **DIVISIBLE** GROUP CHRISTOPHERJ. HILLAR, LIONELLEVINE, ANDDARREN RHEA Abstract. We study equations ingroups Gwithuniquem-throotsforeach positive integer m.

It follows we have 2 jx 10 and 2 ja, so we are done by Theorem 1. 2.2 **Divisibility** by 5 RULE: The number is **divisible** by 5 if the last digits of the number are either 0 or 5.

state of connecticut department of transportation 2800 berlin turnpike, p. o. box 317546 newington, connecticut 06131-7546 telephone (860) 594-2880 fax (860) 594-2949 connecticut **divisible** load permits single unit vehicles maximum permit vehicle type weight axle weights 3 axle - lift 53,800 lbs ...

On **Divisibility** By Nine of the Sums of Even Amicable Pairs By Elvin Lee Abstract. Most known even amicable pairs have sums **divisible** by nine [9]. The general form of the exceptions to the rule of **divisibility** by nine (Gardner's rule) is deduced and the results expressed in the form of a theorem.

**Divisibility** by 7 Problems •Is 623divisibleby 7? Hint: 62 2 3=56. •Is1,234,567,890 **divisible** by 7? Hint: At each step, remove the last digit, double it, and subtract it from what remains.

546460-HM-G5-RT-CH04 546460-HM-G5-RT-CH04. Name Date **Divisibility** The following **divisibility** ruleswill help you determine if a number is **divisible** by 2, 3, 4, 5, 6, 9, and 10.

For example, 23,456 is **divisible** by 4 because 56 is **divisible** by 4, but 25,678 is not **divisible** by 4 because 78 is not **divisible** by 4. 5 if the integer ends in 0 or 5. 75 and 80 are **divisible** by 5, but 77 and 83 are not. 6 if the integer is **divisible** by BOTH 2 and 3. 48 is **divisible** by 6 since it is ...

When we say that 18 is **divisible** by 3, we mean that when 18 is divided by 3, there is a zero remainde r. **Divisible**. Let a and bbewhol e numbers. Then ais **divisible** bybifandonly if the remainder i s zero when ais divided byb.