**mathcentre** community project encouraging academics to share maths support resources All mccpresources are released undera Creative Commons licence community project Mathematical Symbols and Abbreviations mccp-matthews-symbols-001 This leaflet provides information on symbols and notation commonly ...

An AlgebraRefresher v3. February 2003 www.**mathcentre**.ac.uk c * 2003 **mathcentre** ... Foreword The material in this refresher course has been designed to enable you to prepare for your university mathematics programme.

Answer: (e) In a certain geometric sequence, if the first term is 3 and the fifth term is 1875, what is the middle term? Answer: ©Yimin **MathCentre** (www.yiminmathcentre.com)

[5] 2 3 was subtracted from a certain number, then multiplied by 1 1 2 and 1 4 was subtracted. The result was then multiplied by 5 1 5 giving the answer 20. What was the number? ©Yimin **MathCentre** (www.yiminmathcentre.com)

Users are invited to send any suggestions for improvement to enquiries@**mathcentre**.ac.uk. This edition of Basic Differentiation -ARefresher is published by **math centre** in March 2003.

4.6 The sine rule and cosine rule Introduction To solve a triangle is to find the lengths of each of its sides and all its angles. The sine rule is used when we are given eithera) two angles and one side, orb) two sides and anon-included angle.

Finding sin3x in terms of sinx 3 5. Using the formulae to solve an equation 4 1 mc-TY-doubleangle-2009-1 www.**mathcentre**.ac.uk c **mathcentre** July 1, 2009

Triangle formulae A common mathematical problem is to find the angles or lengths of the sides of a triangle when some, but not all of these quantities are known.

... Nationally Funded Engineering Maths & Stats Projects **mathcentre** **mathcentre** is the web-based UK Mathematics Learning Support Centre and has been set up to deliver mathematics support materials, free of charge, to students, teachers, lecturers and everyone looking for post-GCSE maths help. **mathcentre** ...

and there seems to be a pattern because 1 = 2− 1 3 2 = 2− 1 2 7 4 = 2− 1 4 15 8 = 2− 1 8 . c **mathcentre** June 23, 2009 www.**mathcentre**.ac.uk 12 mc-TY-apgp-2009-1